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一轮复习 第3节 简单的逻辑联结词、全称量词与存在量词


第三节 简单的逻辑联结词、全称量词与存在量词
【学习目标】

(1)含有 (2)含有 3.命题的否定 (1)全称命题的否定是 (2)p 或 q 的否定: 4.简单的逻辑联结词 命题中的“

的命题叫全称命题. 的命题叫特称命题.

学 学

1.了解逻辑联结词“或”、“且”、“非”的含义;

2.理解全称量词与存在量词的意义;能正确地对含有一个量词的命题进行否定. 3.激情投入,合作探究,扎实记忆,培养逻辑推理能力. 【重点难点】

命题;特称命题的否定是 ;p 且 q 的否定: .

命题.

”、“

”、“

”叫作逻辑联结词.

案 案

教学重点:p∧q,p∨q, ? p 命题真假的判断、全称命题与特称命题真假的判断; 教学难点:含有一个量词的命题进行否定; 【今日赠言】 岁寒,然后知松柏之后凋也。

5.命题 p∧q、p∨q、 ? p 真假的判断 p 真 真 q 真 假 真 假 p∧q p∨q

?p







装 装

假 假

【知识准备】 1.全称量词与存在量词的定义; 2.全称命题与特称命题;3.含有一个量词命题形式 的否定;

6.含有一个量词的命题的否定 命题 ?x∈M,p(x) ?x0∈M,p(x0) 【预习自测】
1. 判断下面结论是否正确(请在括号中打“√”或“×”)

命题的否定

订 订

【预习导学】 1.全称量词与存在量词

线 线

(1)命题且 q 为假命题,则命题 p、q 都是假命题. (2)已知命题 p:存在 n0∈N,2n0>1 000,则 ? p:存在 n∈N,2n0≤1 000. (3)命题 p 和 ? p 不可能都是真命题. (4)命题“任意 x∈R,x2≥0”的否定是“任意 x∈R,x2<0”. 2. (2013· 重庆)命题“对任意 x∈R,都有 x ≥0”的否定为 A.对任意 x∈R,都有 x2<0 B.不

1.呕0 B不

1.呕0 B不М不Э

(1
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